Salve,
siccome il mio obiettivo era la creazione di un sito (joomla 2.5.6) multilingua senza l'utilizzo di estensioni terze, stavo seguendo la guida presente su questo sito:
http://www.scribd.com/doc/82768844/Joomla-2-5-multi-language-website-without-using-3rd-extensions-in-10-stepsPurtroppo però, quando entro in Estensioni - Gestione Lingua - Contenuti mi esce fuori questo errore:
500 - Si è verificato un errore.
[size=78%]Unknown column 'a.access' in 'on clause' SQL=SELECT a.*,ag.title AS access_level,l.home AS home FROM `jhf25_languages` AS a LEFT JOIN jhf25_viewlevels AS ag ON ag.id = a.access LEFT JOIN `jhf25_menu` AS l ON l.language = a.lang_code AND l.home=1 AND l.language <> '*' WHERE (a.published IN (0, 1)) ORDER BY a.title asc Unknown column 'a.access' in 'on clause' SQL=SELECT a.*,ag.title AS access_level,l.home AS home FROM `jhf25_languages` AS a LEFT JOIN jhf25_viewlevels AS ag ON ag.id = a.access LEFT JOIN `jhf25_menu` AS l ON l.language = a.lang_code AND l.home=1 AND l.language <> '*' WHERE (a.published IN (0, 1)) ORDER BY a.title asc LIMIT 0, 20 Unknown column 'a.access' in 'on clause' SQL=SELECT a.*,ag.title AS access_level,l.home AS home FROM `jhf25_languages` AS a LEFT JOIN jhf25_viewlevels AS ag ON ag.id = a.access LEFT JOIN `jhf25_menu` AS l ON l.language = a.lang_code AND l.home=1 AND l.language <> '*' WHERE (a.published IN (0, 1)) ORDER BY a.title asc[/size]
Qualcuno può aiutarmi?
Grazie mille.
